<u,v> = |u| * |v| * cos?. It's obvious that |u| * cos? means the length of u along v and |v|*cos? means the length of v along u. So if |u| == |v|, they will be equal.
haotingl
yes it is
idkLinearAlgebra
Yes
samalex
yes
banana
Yes it is symmetric!
yumz
I normally visualize the length of v along u to be |v|cos(theta) as well, similar to @coolbreeze. so these two quantities are not equal for me...
notme
Since u and v are the same length in this case, it will be symmetric because of similar triangles.
yes
Yes
Yes
yes
yes
<u,v> = |u| * |v| * cos?. It's obvious that |u| * cos? means the length of u along v and |v|*cos? means the length of v along u. So if |u| == |v|, they will be equal.
yes it is
Yes
yes
Yes it is symmetric!
I normally visualize the length of v along u to be |v|cos(theta) as well, similar to @coolbreeze. so these two quantities are not equal for me...
Since u and v are the same length in this case, it will be symmetric because of similar triangles.
Yes, this property is symmetric
it is symmetric for unit vectors
Yes it is!
Yes!
yes