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BryceSummers
- Vertex is called $V$. The normal vector of $V$ is $T$, assume that $T$ is normalized.
- Compute $V'$ = average of the positions of the neighbors of $V$.
- Let dV = $V' - V$.
- Let dT = $(dV \cdot T) \cdot T$// Projection of dV onto T. (Involves a dot product calculation and then a scalar multiplication operation.)
- Update the value of $V$ to be $V' - dT$