The inverse function $P^{-1}(x)$ is just the derivative of $P(x)$, correct?

Edit: Nevermind, I see that you have to find a constant value to make the integral of a PDF over a given domain equal 1.

The derivative of the CDF P(x) is the pdf p(x).

The inverse function $P^{-1}(x)$ is just the derivative of $P(x)$, correct?

Edit: Nevermind, I see that you have to find a constant value to make the integral of a PDF over a given domain equal 1.

The derivative of the CDF P(x) is the pdf p(x).