The inverse function $P^{-1}(x)$ is just the derivative of $P(x)$, correct?
Edit: Nevermind, I see that you have to find a constant value to make the integral of a PDF over a given domain equal 1.
The derivative of the CDF P(x) is the pdf p(x).
The inverse function $P^{-1}(x)$ is just the derivative of $P(x)$, correct?
Edit: Nevermind, I see that you have to find a constant value to make the integral of a PDF over a given domain equal 1.
The derivative of the CDF P(x) is the pdf p(x).