I was wondering if anyone could clarify since the u,v coordinates are for the unit triangle, we do not have to divide u by (p1-p0) and v by (p2-p0) to get the barycentric coordinates? Since the coordinate are already normalized.
I was wondering if anyone could clarify since the u,v coordinates are for the unit triangle, we do not have to divide u by (p1-p0) and v by (p2-p0) to get the barycentric coordinates? Since the coordinate are already normalized.