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compgraphicsluvr123

Why can't we do this with quadratic Bezier curves? It seems like only the degrees of freedom increases, while the # of constraints stays the same, meaning DOF > # of constraints so we can find a satisfying assignment of control points.

nsp

The DoF decreases, because we are moving from cubic Bezier (3rd order curve made by weighting 4 basis functions) to quadratic (2nd order curve made by weighting 3 basis functions)