Sqare-root of determinant of 3 terms is less intuitive (geometrically, for me) than u x v = ||u|| ||v|| sin(theta) n, for orthogonal unit vector n satisfying right-hand rule
Sqare-root of determinant of 3 terms is less intuitive (geometrically, for me) than u x v = ||u|| ||v|| sin(theta) n, for orthogonal unit vector n satisfying right-hand rule