Even though there is redundant storage, I think it is efficient. Because if we only maintain one copy of the vertex, we need to store the address or index of this vertex, every time I need to get the whole information, we may need to find this copy though pointer or index, etc.
Even though there is redundant storage, I think it is efficient. Because if we only maintain one copy of the vertex, we need to store the address or index of this vertex, every time I need to get the whole information, we may need to find this copy though pointer or index, etc.