I remember in class somebody asked about the case where two meshes cross each other resembling the top right image but still remain manifold. Just wanted to confirm, is it because the manifold meshes' actual representations do not contain the edge of their crossing that they remain manifold?
rohta
It was really helpful in my understanding of manifold meshes when Professor Crane crumpled up the paper and gave a physical example of "flattenable"!
Luke
I was not present for this class, so can someone confirm the answer for this question?
Max
The hourglass and self-intersecting shapes are not manifold, the rest are.
However, if we assumed the hourglass was not attached at the midpoint, or the self-intersecting shape was not attached to itself along the intersection, they could both be manifold as well.
(@outousan - yes, if the intersection does not share the edge, the shape can be manifold and self-intersecting)
I remember in class somebody asked about the case where two meshes cross each other resembling the top right image but still remain manifold. Just wanted to confirm, is it because the manifold meshes' actual representations do not contain the edge of their crossing that they remain manifold?
It was really helpful in my understanding of manifold meshes when Professor Crane crumpled up the paper and gave a physical example of "flattenable"!
I was not present for this class, so can someone confirm the answer for this question?
The hourglass and self-intersecting shapes are not manifold, the rest are.
However, if we assumed the hourglass was not attached at the midpoint, or the self-intersecting shape was not attached to itself along the intersection, they could both be manifold as well.
(@outousan - yes, if the intersection does not share the edge, the shape can be manifold and self-intersecting)