We used the gradient for a linear term and the hessian for the quadratic term… is there any way we could keep moving forward or are there no closed form / easy expressions for these terms?
jefftan
How expensive is the Hessian to compute? Is the extra cost of using the second derivative worth the increased accuracy of the approximation?
We used the gradient for a linear term and the hessian for the quadratic term… is there any way we could keep moving forward or are there no closed form / easy expressions for these terms?
How expensive is the Hessian to compute? Is the extra cost of using the second derivative worth the increased accuracy of the approximation?