Previous | Next --- Slide 27 of 50
Back to Lecture Thumbnails
saphirasnow

We note that this is pretty good despite its assumptions - can we do better by predicting the distribution of the rays somehow?

dchen2

How often do we encounter convex objects? Can we circumvent the convexity assumption by modeling a concave shape as the difference of convex shapes?

sm022

Are there certain applications where we want to use a specific, different type of heuristic? If so, what are some examples of those cases and the different heuristics used?

daria

I assume SN is the surface are of the parent and SA is the surface area of one of the children?

richardnnn

Why this estimate does not apply to the non-convex cases?

jonasjiang

If A is not convex, what will be the consequence of using this heuristic? It seems just the same as the convex condition.

Joshua

Is it a good way to try to find a convex primitive or partition the primitive to convex shape that helps this method?

minhsual

How can we estimate the probabilities when the assumptions do not hold in practice?

twizzler

What other heuristics are there when modeling intersection probability when you have occlusion. I see that it doesn't make sense to assume that you will have a strange ray distribution, but occluding objects occur pretty often from what I understand.

coolpotato

How would you compute these probabilities if there is occlusion? Occlusion seems to occur quite often in the real world.

David

This formula seems pretty general. Why is it only for convex polygons?

kurt

Can this be applied to non-convex polygons by doing some transformations?

TejasFX

Does the polygon being convex really matter? Additionally, if we were to remove the uniform ray distribution assumption and use some other distribution for the rays, would that lead to a noticeable different in actual runtime?

Bellala

Does this work on all geometries? Is there a general computation for them?

anag

If A is totally inside B, why does the convex part need to hold?