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dchen2

I'm guessing that here we assume the surface is smooth so that in particular, there is a plane tangent to the surface at the point of interest and that is why we only integrate over a hemisphere. What if our surface was not smooth?

richardnnn

Or we could have a clear surface? Which means light can come from bottom half plane?

daria

How big is H?

large_monkey

Is this something that is easily approximated with low resource overhead? For instance, if we want to approximate an integral like this, it may require storing a very large explicit representation of a surface, supposing that we would like to use approximate methods and not precise symbolic integration.