Previous | Next --- Slide 23 of 52
Back to Lecture Thumbnails
asheng2

How can we account for multiple light sources when we do direct lighting? Would we now have multiple integrals, each corresponding to a different light source?

saphirasnow

Clarification question: is this change of variables just changing the region of integration from the whole hemisphere of angles to just that subset of angles that intersects the light area?

wmarango

It seems like this technique would completely miss reflected light (unless the reflected light also happened to be in the direction of the light source). How do we account for that?

Edit: oh this is seen later

twizzler

If you had multiple light sources, would you need to do each one separately and add them up?

coolpotato

So instead of integrating over all the possible directions of incoming light of our sample points, we now are integrating over all the outgoing light such that the direction of the light hits our sample points?

urae

How would this method take account of reflected or refracted lights?

spookyspider

Is this saying, we're only going to take samples at each point when the solid angle is coming from the 'area of the light source'?

derk

How would we reformat this equation/method to accommodate multiple lights?

fzeng

Can we just approximate the binary visibility function for the small area to be the same at all points for simplicity and speed?

siamese

It seems like this is only for one light source, but as many have asked, how do we deal with the case when there are multiple light sources? Are we supposed to calculate them separately or can this equation be modified to accomodate multiple light sources?