So the unit of this would then be W/m^3?
yeah, you're right! W/m^2/m = W/m^3 since wavelength is measured in m as well.
If fluorescent lightbulbs only give off a small portion of the light energy that LEDs do, why do LEDs consume so much less power?
So the unit of this would then be W/m^3?
yeah, you're right! W/m^2/m = W/m^3 since wavelength is measured in m as well.
If fluorescent lightbulbs only give off a small portion of the light energy that LEDs do, why do LEDs consume so much less power?