I know probably Keenan intentionally did it, but I just want to "correct" it here. It is not a(u+v) = au + bv. It should be a(u+v) = au + av.
I know probably Keenan intentionally did it, but I just want to "correct" it here. It is not a(u+v) = au + bv. It should be a(u+v) = au + av.