If we wanted to get a vector with the angle theta1 - theta2, would we take the inverse of z2 and multiply it with z1?
motoole2
For complex numbers z_1 and z_2 expressed in polar form, their complex division would give z_1 / z_2 = (r_1 / r_2, \theta_1 - \theta_2). So yes, that would be a way to produce a complex number with angle \theta_1 - \theta_2.
If we wanted to get a vector with the angle theta1 - theta2, would we take the inverse of z2 and multiply it with z1?
For complex numbers
z_1andz_2expressed in polar form, their complex division would givez_1 / z_2 = (r_1 / r_2, \theta_1 - \theta_2). So yes, that would be a way to produce a complex number with angle\theta_1 - \theta_2.