If we wanted to get a vector with the angle theta1 - theta2, would we take the inverse of z2 and multiply it with z1?

motoole2

For complex numbers z_1 and z_2 expressed in polar form, their complex division would give z_1 / z_2 = (r_1 / r_2, \theta_1 - \theta_2). So yes, that would be a way to produce a complex number with angle \theta_1 - \theta_2.

If we wanted to get a vector with the angle theta1 - theta2, would we take the inverse of z2 and multiply it with z1?

For complex numbers

`z_1`

and`z_2`

expressed in polar form, their complex division would give`z_1 / z_2 = (r_1 / r_2, \theta_1 - \theta_2)`

. So yes, that would be a way to produce a complex number with angle`\theta_1 - \theta_2`

.