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munchkin

Why isn't it the way that the smaller t is, the more black the color at x is? From the equation that calculates the color at x, it seems that the computation is opposite as in the picture of the triangle.

joel

Yes, I believe there's a typo. The color should be computed as t * [0 0 1] + (1-t) * [0 0 0]

keenan

blue = large value (1) black = small value (0)

The barycentric coordinate for vertex c should get bigger as we approach c, so that when we're at c the triple of barycentric coords is equal to (0,0,1).

keenan

Ah, right. Yes, @joel is right - I didn't notice the expression for the color itself.