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Haboric

Should $$X(\mathbf{x}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$ be $$X(\mathbf{u}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$ ?

keenan

Yes, that's a typo. Thanks!

taoy1

So $ \nabla F $ means gradient and $ \nabla \cdot X $ is divergence..

keenan

@taoy1 Yes, that's correct. You might find it useful to take a look at the Wikipedia page on the "nabla" or "del" operator

taoy1

Oh that's extremely useful, thank you!