Should
$$X(\mathbf{x}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$
be
$$X(\mathbf{u}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$
?
keenan
Yes, that's a typo. Thanks!
taoy1
So $ \nabla F $ means gradient and $ \nabla \cdot X $ is divergence..
Should $$X(\mathbf{x}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$ be $$X(\mathbf{u}) = \left(X_1(\mathbf{u}),\ldots,X_n(\mathbf{u})\right)$$ ?
Yes, that's a typo. Thanks!
So $ \nabla F $ means gradient and $ \nabla \cdot X $ is divergence..
@taoy1 Yes, that's correct. You might find it useful to take a look at the Wikipedia page on the "nabla" or "del" operator
Oh that's extremely useful, thank you!